LeetCode刷题 NO.181 超过经理收入的员工 (简单)

编写一个SQL查询来查找收入比经理高的员工。

表：Employee

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| name        | varchar |
| salary      | int     |
| managerId   | int     |
+-------------+---------+
Id是该表的主键。
该表的每一行都表示雇员的ID、姓名、工资和经理的ID。

示例

输入: 
Employee 表:
+----+-------+--------+-----------+
| id | name  | salary | managerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | Null      |
| 4  | Max   | 90000  | Null      |
+----+-------+--------+-----------+
输出: 
+----------+
| Employee |
+----------+
| Joe      |
+----------+
解释: Joe 是唯一挣得比经理多的雇员。

代码示例

select e1.name as Employee from Employee as e1 left join Employee e2
on e1.managerId = e2.id
where e1.salary > e2.salary

执行用时：386 ms, 在所有 MySQL 提交中击败了 74.90% 的用户.